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x^2-1.7x+0.5=0
a = 1; b = -1.7; c = +0.5;
Δ = b2-4ac
Δ = -1.72-4·1·0.5
Δ = 0.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.7)-\sqrt{0.89}}{2*1}=\frac{1.7-\sqrt{0.89}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.7)+\sqrt{0.89}}{2*1}=\frac{1.7+\sqrt{0.89}}{2} $
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